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2022

Physics

POST UTME

A body moving with an initial velocity of 20m/s accelerates uniformly at a rate of 40m/s. What is the distance covered during this period?

A.

100m

B.

85m

C.

70m

D.

60m

Correct Answer:

60m

Explanation

Given: u= 20m/s, a = 10m/s, v = 40m/s, s=

using, v2v^2 = u2u^2 + 2as

40240^2 = 20220^2 + 2 ×\times 10 ×\times s

1600 = 400 +20s

1600 - 400 = 20s

1200 = 20s

s = 60m

Given: u= 20m/s, a = 10m/s, v = 40m/s, s=

using, v2v^2 = u2u^2 + 2as

40240^2 = 20220^2 + 2 ×\times 10 ×\times s

1600 = 400 +20s

1600 - 400 = 20s

1200 = 20s

s = 60m

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