2022
Physics
POST UTME
A body performing simple harmonic motion has a frequency of 10Hz and an amplitude of 50Hz and an amplitude of 5cm. Calculate its velocity at a distance of 4cm from the centre of oscillation. [ = 3.14].
A.
4.02m/s
B.
3.14m/s
C.
2.15m/s
D.
1.88m/s
Correct Answer: 1.88m/s
Explanation
using,v =
where A = 5cm, x =4cm
;
x x10
x x
1.88cm/s
in m/s we divide by 100
1.88m/s
using,v =
where A = 5cm, x =4cm
;
x x10
x x
1.88cm/s
in m/s we divide by 100
1.88m/s