Explanation

heat loss by copper = Heat gain by ice

$mc\theta = ml$

copper is from boiling water

$\Delta$ $\theta$ = 100$^0C$

$1 \times - 400 \times 100 = m \times -33300$

m = $\frac {-40000}{333000} = 120g$

heat loss by copper = Heat gain by ice

$mc\theta = ml$

copper is from boiling water

$\Delta$ $\theta$ = 100$^0C$

$1 \times - 400 \times 100 = m \times -33300$

m = $\frac {-40000}{333000} = 120g$