2000
Mathematics
67ca00ce0c643c71d77dee1f
In how many ways can a delegation of 3 be chosen from among 5 men and 3 women, if at least one man and at least one woman must be included?
A.
15
B.
28
C.
30
D.
45
Correct Answer: 45
Explanation
No of ways of choosing 1 man, 2 women = 5C1 x 3C2 No of ways of choosing 2 men, 1 woman = 5C2 x 3C1 Summing, => (5C1 x 3C2) + (5C2 x 3C1) = 15 + 30 = 45
No of ways of choosing 1 man, 2 women = 5C1 x 3C2 No of ways of choosing 2 men, 1 woman = 5C2 x 3C1 Summing, => (5C1 x 3C2) + (5C2 x 3C1) = 15 + 30 = 45THIS WEEK's
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