2000
Mathematics
67ca00ce0c643c71d77dee1f
Find the value of ∫π0(cos2θ−1/sin2θ)*dθ
A.
π
B.
π/2
C.
-π/2
D.
-π
Correct Answer: -π
Explanation
∫π0(cos2θ−1)/(sin2θ)dθ=∫π0(−sin2θ)/sinsin2θ)=∫π0dθ=−π
∫π0(cos2θ−1)/(sin2θ)dθ=∫π0(−sin2θ)/sinsin2θ)=∫π0dθ=−πTHIS WEEK's
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