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2000

Mathematics

67ca00ce0c643c71d77dee1f

Find the value of ∫π0(cos2θ−1/sin2θ)*dθ

A.

π

B.

π/2

C.

-π/2

D.

Correct Answer:

Explanation

∫π0(cos2θ−1)/(sin2θ)dθ=∫π0(−sin2θ)/sinsin2θ)=∫π0dθ=−π

∫π0(cos2θ−1)/(sin2θ)dθ=∫π0(−sin2θ)/sinsin2θ)=∫π0dθ=−π
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