2001
Mathematics
67ca00ce0c643c71d77dee1f
Find the value of θ in the diagram
A.
60°
B.
100°
C.
120°
D.
30°
Correct Answer: 120°
Explanation
Using cosine formula (t√3)2 = t2 + t2 - 2t2 cosθ 3t2 = 2t2 - 2t2 cosθ = 2t2(1 - cosθ) 1 - cosθ = 3t2 / 2t2 = 3/2 cos = 1 - 3/2 = − 1/2 θ = cos-1(-1/2) = 120° and 240° N.B 0 ≥ θ 360
Using cosine formula (t√3)2 = t2 + t2 - 2t2 cosθ 3t2 = 2t2 - 2t2 cosθ = 2t2(1 - cosθ) 1 - cosθ = 3t2 / 2t2 = 3/2 cos = 1 - 3/2 = − 1/2 θ = cos-1(-1/2) = 120° and 240° N.B 0 ≥ θ 360THIS WEEK's
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