2003
Mathematics
67ca00ce0c643c71d77dee1f
Three consecutive terms of a geometric progression are given as n-2, n and n+3. Find the common ratio
A.
1/4
B.
1/2
C.
2/3
D.
3/2
Correct Answer: 3/2
Explanation
r = n/n−2 and r= n+3/n ∴n/n−2= n+3/n n2 = n2 + 3n − 2n − 6. 0 = n−6. ∴ n = 6. But r = n/n−2. r = 6/6−2.6/4 = 3/2
r = n/n−2 and r= n+3/n ∴n/n−2= n+3/n n2 = n2 + 3n − 2n − 6. 0 = n−6. ∴ n = 6. But r = n/n−2. r = 6/6−2.6/4 = 3/2THIS WEEK's
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