2005
Mathematics
67ca00ce0c643c71d77dee1f
Find the derivative of y = sin(2x3 + 3x - 4)
A.
cos (2x3 + 3x - 4)
B.
-cos (2x3 + 3x - 4)
C.
(6x2 + 3) cos (2x3 + 3x - 4)
D.
-(6x2 + 3) cos (2x3 + 3x - 4)
Correct Answer: (6x2 + 3) cos (2x3 + 3x - 4)
Explanation
y = sin (2x3 + 3x - 4) let u = 2x3 + 3x - 4 ∴du/dx = 6x2 y = sin u dy/du = cos u dy/dx = du/dx * dy/du ∴dy/dx = (6x2 + 3) cos u = (6x2 + 3)cos(2x3 + 3x - 4)
y = sin (2x3 + 3x - 4) let u = 2x3 + 3x - 4 ∴du/dx = 6x2 y = sin u dy/du = cos u dy/dx = du/dx * dy/du ∴dy/dx = (6x2 + 3) cos u = (6x2 + 3)cos(2x3 + 3x - 4)THIS WEEK's
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