2005
Mathematics
67ca00ce0c643c71d77dee1f
The weight W kg of a metal bar varies jointly as its length L meters and the square of its diameter d meters. If w = 140 when d = 4(2/3) and L = 54, find d in terms of W and L.
A.
√(42W/5L)
B.
√(6L/42W)
C.
42W/5L
D.
5L/42W
Correct Answer: √(42W/5L)
Explanation
W∞LD2 W=KLd2 K=W/(Ld^2 )=140/54×〖(4 2/3)〗2=140/54×〖(14/3)〗2 = (140×9)/(54×14×14)=5/42∴W=5/(42Ld2 ) 42W=5Ld2 42W/5L=d2 d=√(42W/5L)
W∞LD2 W=KLd2 K=W/(Ld^2 )=140/54×〖(4 2/3)〗2=140/54×〖(14/3)〗2 = (140×9)/(54×14×14)=5/42∴W=5/(42Ld2 ) 42W=5Ld2 42W/5L=d2 d=√(42W/5L)THIS WEEK's
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