passpadi

2006

Mathematics

67ca00ce0c643c71d77dee1f

In the diagram above, PQ = 10 cm, PS = 8 cm and ∠PSR is 60o while ∠SRQ is a right angle. Find SR

A.

14 cm

B.

14√3 cm

C.

10 cm

D.

10√3 cm

Correct Answer: 14 cm

Explanation

In ΔPST; cos 60 = ST/8 ST = 8cos 60 ST = 8 x 1/2 = 4 TR = 10 cm (opp. sides of a rectangle PQRT) SR = ST + TR SR = 4 + 10 SR = 14 cm

In ΔPST; cos 60 = ST/8 ST = 8cos 60 ST = 8 x 1/2 = 4 TR = 10 cm (opp. sides of a rectangle PQRT) SR = ST + TR SR = 4 + 10 SR = 14 cm
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