passpadi

2006

Mathematics

67ca00ce0c643c71d77dee1f

In triangle XYZ, ∠XYZ = 15o, ∠XZY = 45o and lXYl = 7 cm. Find lYZl.

A.

14√2 cm

B.

7(√6/2)

C.

7√2 cm

D.

7 cm

Correct Answer: 7(√6/2)

Explanation

∠yxz = 180 - (45 + 15) = 180 - 60 = 120o Using sine rule x/sinx=7/sinz x/sin120=7/sin45 x=7sin120/sin45 x=(7sin(180-120))/sin45 x=7sin60/sin45=(7(√3/2)÷1/√2)x=(7(√3/2)÷1/√2)x=7(√6/2)

∠yxz = 180 - (45 + 15) = 180 - 60 = 120o Using sine rule x/sinx=7/sinz x/sin120=7/sin45 x=7sin120/sin45 x=(7sin(180-120))/sin45 x=7sin60/sin45=(7(√3/2)÷1/√2)x=(7(√3/2)÷1/√2)x=7(√6/2)
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