2006
Mathematics
67ca00ce0c643c71d77dee1f
IN the diagram above, POQ is a diameter of the circle PQRS. If ∠PSR = 145°, find xo
A.
55°
B.
45°
C.
35°
D.
25°
Correct Answer: 55°
Explanation
∠PSQ = 90° (∠ in semi circle) ∠PSQ + ∠QSR = 145o 90 + ∠QSR = 145 ∠QSR = 145 - 90 ∠QSR = 55° BUt x° = ∠QSR (∠s in the same segment) ∴xo = 55°
∠PSQ = 90° (∠ in semi circle) ∠PSQ + ∠QSR = 145o 90 + ∠QSR = 145 ∠QSR = 145 - 90 ∠QSR = 55° BUt x° = ∠QSR (∠s in the same segment) ∴xo = 55°THIS WEEK's
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