passpadi

2006

Mathematics

67ca00ce0c643c71d77dee1f

Find the roots of x3 - 2x2 - 5x + 6 = 0

A.

1, -2, 3

B.

1, 2, -3,

C.

-1, -2, 3

D.

-1, 2, -3

Correct Answer: 1, -2, 3

Explanation

Equation: x3 - 2x2 - 5x + 6 = 0. First, bring out an which is the coefficient of x3 = 1. Then, aa0 which is the coefficient void of x = 6. The factors of aan = 1; The factors of aa0 = 1, 2, 3 and 6. The numbers to test for the roots are ±(an0/sub>/aan) . = ±(1,2,3,6). Test for +1: 1323222.

Equation: x3 - 2x2 - 5x + 6 = 0. First, bring out an which is the coefficient of x3 = 1. Then, aa0 which is the coefficient void of x = 6. The factors of aan = 1; The factors of aa0 = 1, 2, 3 and 6. The numbers to test for the roots are ±(an0/sub>/aan) . = ±(1,2,3,6). Test for +1: 1323222.
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