2007
Mathematics
67ca00ce0c643c71d77dee1f
Determine the value of ∫0(π/2)(-2cosx)dx
A.
(π/2)
B.
-1/2
C.
-3
D.
-3/2
Correct Answer: (π/2)
Explanation
∫0(π/2)(-2cosx)dx=[-2sinx+c]0(π/2)=(-2sin π/2 + c + 2sin0 - c) = -2sin90 + c + 2sin0 - c.= -2(1) + 2(0) = -2
∫0(π/2)(-2cosx)dx=[-2sinx+c]0(π/2)=(-2sin π/2 + c + 2sin0 - c) = -2sin90 + c + 2sin0 - c.= -2(1) + 2(0) = -2THIS WEEK's
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