2007
Mathematics
67ca00ce0c643c71d77dee1f
Find the value of (tan60°-tan30°)/(tan60°+tan 30° )
A.
4/√3
B.
2/√3
C.
1
D.
1/2
Correct Answer: 1/2
Explanation
(tan〖60〗°-tan〖30〗°)/(tan〖60〗°+tan〖30〗° )=(√3-1/√3)/(√3+1/√3)=((√3 √3-1)/√3)÷((√3 √3+1)/√3)=((3-1))/((3+1))=2/4=1/2
(tan〖60〗°-tan〖30〗°)/(tan〖60〗°+tan〖30〗° )=(√3-1/√3)/(√3+1/√3)=((√3 √3-1)/√3)÷((√3 √3+1)/√3)=((3-1))/((3+1))=2/4=1/2THIS WEEK's
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