2007
Mathematics
67ca00ce0c643c71d77dee1f
Integrate (x2-√x)/x with respect to x
A.
x2/2-2√x+K
B.
(2(x2-x))/3x+K
C.
x2/2-√x+K
D.
((x2-x))/3x+K
Correct Answer: x2/2-2√x+K
Explanation
∫(x2-√x)/x=∫x2/x-x^(1/2)/x∫x-x^((-1)/2)=(1/2)x2-x1/2/(1/2)+K=x2/2-2x1/2+K=x2/2-2√x+K
∫(x2-√x)/x=∫x2/x-x^(1/2)/x∫x-x^((-1)/2)=(1/2)x2-x1/2/(1/2)+K=x2/2-2x1/2+K=x2/2-2√x+KTHIS WEEK's
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