2008
Mathematics
67ca00ce0c643c71d77dee1f
Find the gradient of a line which is perpendicular to the line with the equation 3x + 2y + 1 = 0
A.
3/2
B.
2/3
C.
-2/3
D.
-3/2
Correct Answer: 2/3
Explanation
3X + 2Y + 1 = 0 2Y = -3X - 1 −3/2X−1/2 Gradient of 3X + 2Y +1 = 0 is -3/2 Gradient of a line perpendicular to 3X + 2Y + 1 = 0 =−1÷3/2 = −1 × −2/3 =2/3
3X + 2Y + 1 = 0 2Y = -3X - 1 −3/2X−1/2 Gradient of 3X + 2Y +1 = 0 is -3/2 Gradient of a line perpendicular to 3X + 2Y + 1 = 0 =−1÷3/2 = −1 × −2/3 =2/3THIS WEEK's
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