2008
Mathematics
67ca00ce0c643c71d77dee1f
∫((-π)/2)(π/2)cosxdx
A.
0
B.
1
C.
2
D.
3
Correct Answer: 2
Explanation
∫((-π)/2)(π/2)cosxdx=[sinx((-π)/2)(π/2) = sin π/2-sin (-π)/2. = sin90 – sin-90 = sin90 – sin270 = 1 – (-1) = 1+1 = 2
∫((-π)/2)(π/2)cosxdx=[sinx((-π)/2)(π/2) = sin π/2-sin (-π)/2. = sin90 – sin-90 = sin90 – sin270 = 1 – (-1) = 1+1 = 2THIS WEEK's
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