2012
Mathematics
67ca00ce0c643c71d77dee1f
The probabilities that a man and his wife live for 80 years are 2/3 and 3/5 respectively. Find the probability that at least one of them will live up to 80 years
A.
2/15
B.
3/15
C.
7/15
D.
13/15
Correct Answer: 13/15
Explanation
Man lives = 2/3 not live = 1/3 Wife lives = 3/5 not live = 2/5 P(at least one lives to 80 years) = P(man lives to 80 not woman) + P(woman lives to 80 and not man) + P(both live to 80) P=(2/3 × 2/5) + (2/5 × 1/3) + (2/3 × 3/5) = 4/15 + 3/15 + 6/15 = 13/15
Man lives = 2/3 not live = 1/3 Wife lives = 3/5 not live = 2/5 P(at least one lives to 80 years) = P(man lives to 80 not woman) + P(woman lives to 80 and not man) + P(both live to 80) P=(2/3 × 2/5) + (2/5 × 1/3) + (2/3 × 3/5) = 4/15 + 3/15 + 6/15 = 13/15THIS WEEK's
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