2012
Mathematics
67ca00ce0c643c71d77dee1f
The nth term of a sequence is n2 - 6n - 4. Find the sum of the 3rd and 4th terms
A.
24
B.
23
C.
-24
D.
-25
Correct Answer: -25
Explanation
n2 - 6n - 4 For the 3rd term, 32 - 6(3) - 4 9 - 18 -4 = -13 For the 4th term, 42 - 6(4) - 4 16 - 24 - 4 = -12 Sum of both terms -13 - 12 = -25
n2 - 6n - 4 For the 3rd term, 32 - 6(3) - 4 9 - 18 -4 = -13 For the 4th term, 42 - 6(4) - 4 16 - 24 - 4 = -12 Sum of both terms -13 - 12 = -25THIS WEEK's
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