2013
Mathematics
67ca00ce0c643c71d77dee1f
Integrate 1+x/x3dx
A.
2x2−(1/x) + k
B.
−1/2x2 −1/x + k
C.
−x2/2 − (1/x) + k
D.
x2 − (1/x) + k
Correct Answer: −1/2x2 −1/x + k
Explanation
∫1+x/x3 dx = ∫(1/x3 + x/x3)dx = ∫(x-3 + x-2)dx = −1/2x2 − 1/x + k
∫1+x/x3 dx = ∫(1/x3 + x/x3)dx = ∫(x-3 + x-2)dx = −1/2x2 − 1/x + kTHIS WEEK's
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