2014
Mathematics
67ca00ce0c643c71d77dee1f
Find the minimum value of y = x2 - 2x - 3
A.
4
B.
1
C.
-1
D.
-4
Correct Answer: -4
Explanation
y = x2 - 2x - 3, Then δy/δx = 2x − 2 But at minimum point,δy/δx = 0 , Which means 2x - 2 = 0 2x = 2 x = 1. Hence the minimum value of y = x2 - 2x - 3 is; ymin = (1)2 - 2(1) - 3 ymin = 1 - 2 - 3 ymin= -4
y = x2 - 2x - 3, Then δy/δx = 2x − 2 But at minimum point,δy/δx = 0 , Which means 2x - 2 = 0 2x = 2 x = 1. Hence the minimum value of y = x2 - 2x - 3 is; ymin = (1)2 - 2(1) - 3 ymin = 1 - 2 - 3 ymin= -4THIS WEEK's
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