Calculate the mid point of the line segment y - 4x + 3 = 0, which lies between the x-axis and y-axis.
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B.
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Correct Answer:
Explanation
y - 4x + 3 = 0
When y = 0, 0 - 4x + 3 = 0
Then -4x = -3
x = 3/4
So the line cuts the x-axis at point (3/4, 0).
When x = 0, y - 4(0) + 3 = 0
Then y + 3 = 0
y = -3
So the line cuts the y-axis at the point (0, -3)
Hence the midpoint of the line y - 4x + 3 = 0, which lies between the x-axis and the y-axis is;
[1/2(x1 +x2 ),1/2(y1 +y2 )]
[1/2(3/4+0),1/2(0+−3)]
[1/2(3/4),1/2(−3)]
[3/8,−3/2]
y - 4x + 3 = 0
When y = 0, 0 - 4x + 3 = 0
Then -4x = -3
x = 3/4
So the line cuts the x-axis at point (3/4, 0).
When x = 0, y - 4(0) + 3 = 0
Then y + 3 = 0
y = -3
So the line cuts the y-axis at the point (0, -3)
Hence the midpoint of the line y - 4x + 3 = 0, which lies between the x-axis and the y-axis is;
[1/2(x1 +x2 ),1/2(y1 +y2 )]
[1/2(3/4+0),1/2(0+−3)]
[1/2(3/4),1/2(−3)]
[3/8,−3/2]
