passpadi

2017

Mathematics

67ca00ce0c643c71d77dee1f

Find the equation of the locus of a point p (x, y) such that pv = pw, where v= (1, 1) and w = (3, 5)

A.

2x + 2y = 9

B.

2x + 3y = 8

C.

2x + y = 9

D.

x + 2y = 8

Correct Answer: x + 2y = 8

Explanation

The locus of a point p(x, y) such that pv = pw where v = (1, 1) and w = (3, 5). This means that the point p moves so that its distance from v and w are equidistance √(x−x1)2 +(y−y1)2 = √(x−x2)2 + (y−y2)2 √(x−1)2 +(y−1)2 = √(x−3)2 +(y−5)2 square both sides (x - 1)2 + (y - 1)2 = (x - 3)2 + (y - 5)2 x2 - 2x + 1 + y2 - 2y + 1 = x2 - 6x + 9 + y2 - 10y + 25 x2 + y2 -2x -2y + 2 = x2 + y2 - 6x - 10y + 34 Collecting like terms x2 - x2 + y2 - y2 - 2x + 6x -2y + 10y = 34 - 2 4x + 8y = 32 Divide through by 4 x + 2y = 8

The locus of a point p(x, y) such that pv = pw where v = (1, 1) and w = (3, 5). This means that the point p moves so that its distance from v and w are equidistance √(x−x1)2 +(y−y1)2 = √(x−x2)2 + (y−y2)2 √(x−1)2 +(y−1)2 = √(x−3)2 +(y−5)2 square both sides (x - 1)2 + (y - 1)2 = (x - 3)2 + (y - 5)2 x2 - 2x + 1 + y2 - 2y + 1 = x2 - 6x + 9 + y2 - 10y + 25 x2 + y2 -2x -2y + 2 = x2 + y2 - 6x - 10y + 34 Collecting like terms x2 - x2 + y2 - y2 - 2x + 6x -2y + 10y = 34 - 2 4x + 8y = 32 Divide through by 4 x + 2y = 8
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