2019
Mathematics
67ca00ce0c643c71d77dee1f
The nth term of a sequence is given by 2(2n−1). Find the sum of the first four terms.
A.
74
B.
32
C.
42
D.
170
Correct Answer: 170
Explanation
Tn = 2(2n−1) T1 = 2(2(1)−1 = 2 T2 = 2(2(2)−1) = 8 T3 = 2(2(3)−1) = 32 T4 = 2(2(4)−1) = 128 T1+T2+T3+T4 = 2 + 8 + 32 + 128 = 170
Tn = 2(2n−1) T1 = 2(2(1)−1 = 2 T2 = 2(2(2)−1) = 8 T3 = 2(2(3)−1) = 32 T4 = 2(2(4)−1) = 128 T1+T2+T3+T4 = 2 + 8 + 32 + 128 = 170THIS WEEK's
Latest Articles
Top-Scorer Okoro Uchechukwu Solomon Reveals How He Scored 337 in JAMB
by samuel olalekan adeyemi
Bouncing Back: How Samuel Isaac Overcame Setbacks to Score 265 in JAMB and What He Learned
by samuel olalekan adeyemi
Managing Stress During Exams: Practical Tips for Students
by samuel olalekan adeyemi
