2008
Mathematics
67ca00ce0c643c71d77dee1f
Find the minimum value of the function y = x(1+x)
A.
-1/4
B.
-1/2
C.
1/4
D.
1/2
Correct Answer: -1/4
Explanation
y = x(1+x) = x + x2 dy/dx = 1 + 2x As dy/dy → 0 1 + 2x = 0 2x = -1 X = -1/2 Y = x(1+x) = -1/2(1 - 1/2) at x = -1/2 = -1/2(1/2) = -1/4
y = x(1+x) = x + x2 dy/dx = 1 + 2x As dy/dy → 0 1 + 2x = 0 2x = -1 X = -1/2 Y = x(1+x) = -1/2(1 - 1/2) at x = -1/2 = -1/2(1/2) = -1/4THIS WEEK's
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