2020
Mathematics
67ca00ce0c643c71d77dee1f
Three consecutive terms of a geometric progression are give as n - 2, n and n + 3. Find the common ratio
A.
3/2
B.
2/3
C.
1/2
D.
1/4
Correct Answer: 3/2
Explanation
h/(n − 2) = (n + 3)/n n2 = (n + 3) (n - 2) n2 = n2 + n - 6 n22 + n - 6 - n2 = 0 n - 6 = 0 n = 6 Common ratio: n/(n−2) = 6/(6 −2) = 6/4 = 3/2
h/(n − 2) = (n + 3)/n n2 = (n + 3) (n - 2) n2 = n2 + n - 6 n22 + n - 6 - n2 = 0 n - 6 = 0 n = 6 Common ratio: n/(n−2) = 6/(6 −2) = 6/4 = 3/2THIS WEEK's
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