passpadi

2020

Mathematics

67ca00ce0c643c71d77dee1f

The equation of the line in the graph is

A.

3y = 3x + 12

B.

3y = 3x + 12

C.

3y = -4x + 12

D.

3y = -4x + 9

Correct Answer: 3y = -4x + 12

Explanation

Gradient of line = Change in y/Change in x = (y2 −Y1)/(x2 − x1) y2 = 01 Y1 = 4 x2 = 3 and x1 = 0 (y2 − y1 )/(x2 − x1 ) = (0−4)/(3 − 0) = −4/3 Equation of straight line y = mx + c Where m = gradient and c = y intercept = 4 y = -4/3x + 4 multiply through by 3 3y = -4x + 12

Gradient of line = Change in y/Change in x = (y2 −Y1)/(x2 − x1) y2 = 01 Y1 = 4 x2 = 3 and x1 = 0 (y2 − y1 )/(x2 − x1 ) = (0−4)/(3 − 0) = −4/3 Equation of straight line y = mx + c Where m = gradient and c = y intercept = 4 y = -4/3x + 4 multiply through by 3 3y = -4x + 12
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