passpadi

2009

Mathematics

67ca00ce0c643c71d77dee1f

If log102 = 0.3010 and log107 = 0.8451, evaluate log10280

A.

3.4471

B.

2.4471

C.

1.4471

D.

1.4071

Correct Answer: 2.4471

Explanation

Log 2 = 0.3010, Log 7 = 0.8451 ∴Log 280 = Log 28 x 10 = Log 7x4x10 =Log7 + Log4 + Log10 = Log7 + Log22 + Log10 = Log7 + 2Log2 + Log10 = 0.8451 + 2(0.3010) + 1 = 0.8451 + 0.6020 + 1 = 2.4471

Log 2 = 0.3010, Log 7 = 0.8451 ∴Log 280 = Log 28 x 10 = Log 7x4x10 =Log7 + Log4 + Log10 = Log7 + Log22 + Log10 = Log7 + 2Log2 + Log10 = 0.8451 + 2(0.3010) + 1 = 0.8451 + 0.6020 + 1 = 2.4471
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