2013
Mathematics
67ca00ce0c643c71d77dee1f
The nth term of the progression 4/2, 7/3, 10/4, 13/5 is ...
A.
(1−3n)/(n+1)
B.
(3n + 1)/(n+1)
C.
(3n + 1)/(n-1)
D.
3n - 1)/(n+1)
Correct Answer: (3n + 1)/(n+1)
Explanation
Using Tn = (3n+1)/(n+1), T1 = 3(1)+1/(1)+1 = 4/2 T2 = (3(2)+1)/((2)+1) = 7/3 T3 = (3(3) +1/((3)+1) = 10/4
Using Tn = (3n+1)/(n+1), T1 = 3(1)+1/(1)+1 = 4/2 T2 = (3(2)+1)/((2)+1) = 7/3 T3 = (3(3) +1/((3)+1) = 10/4THIS WEEK's
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