2022
Mathematics
67ca00ce0c643c71d77dee1f
If sec2θ + tan2θ = 3, then the angle θ is equal to?
A.
90°
B.
30°
C.
45°
D.
60°
Correct Answer: 45°
Explanation
Given that sec2θ + tan2 θ = 3 Where sec2θ = 1 + tan2θ : 1 + tan2 θ + tan2 θ = 3 2tan2θ = 3 - 1 2tan2θ = 2 divide both sides by 2 tan2θ = 1 tanθ = √1 tanθ = 1 θ = tan−1(1) θ = 45°
Given that sec2θ + tan2 θ = 3 Where sec2θ = 1 + tan2θ : 1 + tan2 θ + tan2 θ = 3 2tan2θ = 3 - 1 2tan2θ = 2 divide both sides by 2 tan2θ = 1 tanθ = √1 tanθ = 1 θ = tan−1(1) θ = 45°THIS WEEK's
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