passpadi

2004

Mathematics

67ca00ce0c643c71d77dee1f

find the mean deviation of 1, 2, 3 and 4

A.

2.5

B.

2.0

C.

1.0

D.

1.5

Correct Answer: 1.0

Explanation

X = 1, 2, 3, 4; ∑X = 10 x = ∑X/n = 10/4 = 2.5 X - x = -1.5, -0.5, 0.5, 1.5 lX - xl = 1.5, 0.5, 0.5, 1.5; ∑lX - xl = 4.0 mean deviation = (∑lX - xl)/n = 4.0/4 = 1.0

X = 1, 2, 3, 4; ∑X = 10 x = ∑X/n = 10/4 = 2.5 X - x = -1.5, -0.5, 0.5, 1.5 lX - xl = 1.5, 0.5, 0.5, 1.5; ∑lX - xl = 4.0 mean deviation = (∑lX - xl)/n = 4.0/4 = 1.0
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