2016
Mathematics
67ca00ce0c643c71d77dee1f
Integrate (2x3+2x)/x with respect to x
A.
2x3/3 - 2x + k
B.
x3 + 2x + k
C.
2x3/3 + 2x + k
D.
x3 - 2x + k
Correct Answer: 2x3/3 + 2x + k
Explanation
∫ (2x3+2x)/x = ∫2x3/x + 2x/x = ∫ (2x3 + 2)dx (2x2+1)/(2+1) + 2x + k = 2x3/3+ 2x + k
∫ (2x3+2x)/x = ∫2x3/x + 2x/x = ∫ (2x3 + 2)dx (2x2+1)/(2+1) + 2x + k = 2x3/3+ 2x + kTHIS WEEK's
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