2004
Mathematics
67ca00ce0c643c71d77dee1f
In the diagram above, PQ = 4 cm and TS = 6 cm. If the area of parallelogram PQTU is 32 cm 2, find the area of the trapezium PQRU
A.
60 cm2
B.
72 cm2
C.
48 cm2
D.
24 cm2
Correct Answer: 72 cm2
Explanation
Area of parallelogram PQTU = base * height 32 = 4 * h w = 32/4 w = 8 ∴ = Area of Trapezium PQRU = (1/2)(4 + 14) *8 = 1/2 * (18 * 8) = 72 cm2
Area of parallelogram PQTU = base * height 32 = 4 * h w = 32/4 w = 8 ∴ = Area of Trapezium PQRU = (1/2)(4 + 14) *8 = 1/2 * (18 * 8) = 72 cm2THIS WEEK's
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