2004
Mathematics
JAMB
Factorize completely ac - 2bc - a + 4b2
A.
(a - 2b)(c - a - 2b)
B.
(a - 2b)(c + a +2b)
C.
(a - 2b)(c - a + 2b)
D.
(a - 2b)(c + a - 2b)
Correct Answer: (a - 2b)(c - a - 2b)
Explanation
ac - 2bc - a2 + 4b2 ac - 2bc - (a2 - 4b2) ac - 2bc - (a2 -(2b)2) c(a - 2b) - {(a - 2b)(a + 2b)} (a - 2b)(c - (a + 2b)) (a - 2b)(c - a - 2b)
ac - 2bc - a2 + 4b2 ac - 2bc - (a2 - 4b2) ac - 2bc - (a2 -(2b)2) c(a - 2b) - {(a - 2b)(a + 2b)} (a - 2b)(c - (a + 2b)) (a - 2b)(c - a - 2b)THIS WEEK's
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