passpadi

2004

Mathematics

JAMB

Find the derivatives of the function y = 2x2(2x - 1) at the point x = -1

A.

18

B.

16

C.

-4

D.

-6

Correct Answer: 16

Explanation

y = 2x2(2x - 1) y = 4x3 - 2x2 dy/dx = 12x2 - 4x at x = -1 dy/dx = 12(-1)2 - 4(-1) = 12 + 4 = 16

y = 2x2(2x - 1) y = 4x3 - 2x2 dy/dx = 12x2 - 4x at x = -1 dy/dx = 12(-1)2 - 4(-1) = 12 + 4 = 16
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