2004
Mathematics
JAMB
PQRSTV is a regular polygon of side 7 cm inscribed in a circle. Find the circumference of the circle PQRSTV.
A.
56 cm
B.
22 cm
C.
42 cm
D.
44 cm
Correct Answer: 44 cm
Explanation
Each interior Angle of the polygon = (n-2) 180 _n = (6-2) 180 _6 = 4 x 30 = 120° i.e ∠PQR = 120° ∴ RQD = 120/2 = 60° also ∴ Δ QOR is equilateral Δ ∴ QO = 7cm ∴ PO = QO = RO ...... = 7cm radius of the circumference of the circle = 2πr = 2 x 22/7 x 7/1 = 44 cm
Each interior Angle of the polygon = (n-2) 180 _n = (6-2) 180 _6 = 4 x 30 = 120° i.e ∠PQR = 120° ∴ RQD = 120/2 = 60° also ∴ Δ QOR is equilateral Δ ∴ QO = 7cm ∴ PO = QO = RO ...... = 7cm radius of the circumference of the circle = 2πr = 2 x 22/7 x 7/1 = 44 cmTHIS WEEK's
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