passpadi

2003

Mathematics

JAMB

In the diagram above, PQR is a straight line and PS is a tangent to the circle QRS with /PS/ = /SR/ and ∠SPR = 40o. Find ∠PSQ

A.

40°

B.

30°

C.

20°

D.

10°

Correct Answer: 40°

Explanation

R = P (base ∠s of isc Δ, ps = RS) ∴R = 40o ∠PSQ = R (∠s in alternate segment) ∴∠PSQ = 40°

R = P (base ∠s of isc Δ, ps = RS) ∴R = 40o ∠PSQ = R (∠s in alternate segment) ∴∠PSQ = 40°
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