2003
Mathematics
JAMB
An aeroplane flies due north from airport P to Q and then flies due east R. If Q is equidistant from P and R, find the bearing of P and R
A.
90°
B.
135°
C.
225°
D.
270°
Correct Answer: 225°
Explanation
Since PQ = QR, Δ PQR is a right angle isosceles triangle ∴ ∠PQR = 45° => The bearing of P from R = 180 + 45 = 225°
Since PQ = QR, Δ PQR is a right angle isosceles triangle ∴ ∠PQR = 45° => The bearing of P from R = 180 + 45 = 225°THIS WEEK's
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