2003
Mathematics
JAMB
A bag contains 5 blacks balls and 3 red balls. Two balls are picked at random without replacement. What is the probability that a black and red balls are picked?
A.
15/28
B.
13/28
C.
5/14
D.
3/14
Correct Answer: 15/28
Explanation
Black balls = 5 Red balls = 3/8 P(B) = 5/8, P(R) = 3/8 P( a Black and a Red) = BR + RB = (5/8) * (3/7) * (3/8) * (5/7) = (15/56) + (15/56) = 30/56 = 15/28
Black balls = 5 Red balls = 3/8 P(B) = 5/8, P(R) = 3/8 P( a Black and a Red) = BR + RB = (5/8) * (3/7) * (3/8) * (5/7) = (15/56) + (15/56) = 30/56 = 15/28THIS WEEK's
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