2002
Mathematics
JAMB
If y=x2−1x. find dy/dx
A.
2x - (1/x2)
B.
2x + x2
C.
2x - x2
D.
2x + (1/x2)
Correct Answer: 2x + (1/x2)
Explanation
y=x2−1/x = x2− x-1 dy/dx = 2x − ( −x-2) = 2x + 1/x2
y=x2−1/x = x2− x-1 dy/dx = 2x − ( −x-2) = 2x + 1/x2THIS WEEK's
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