2002
Mathematics
JAMB
Evaluate ∫sin3xdx
A.
(2/3) cos 3x + c
B.
(1/3) cos 3x + c
C.
(-1/3) cos 3x + c
D.
(-2/3) cos 3x + c
Correct Answer: (-1/3) cos 3x + c
Explanation
∫sin3xdx=−cos3x/3 + c = −1/3 (cos 3x) + c
∫sin3xdx=−cos3x/3 + c = −1/3 (cos 3x) + cTHIS WEEK's
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