2002
Mathematics
67ca00ce0c643c71d77dee1f
If dy/dx = 2x - 3 and y = 3 when x = 0, find y in terms of x.
A.
2x2 - 3x
B.
x2 - 3x
C.
2x2 - 3x - 3
D.
2x2 - 3x + 3
Correct Answer: 2x2 - 3x + 3
Explanation
dy/dx = 2x - 3 y = ∫2x - 3 dx => y = xx2 - 3x + c 3 = (0)2 - 3(0) + c => c = 3 Thus y = x2 - 3x + 3
dy/dx = 2x - 3 y = ∫2x - 3 dx => y = xx2 - 3x + c 3 = (0)2 - 3(0) + c => c = 3 Thus y = x2 - 3x + 3THIS WEEK's
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