passpadi

2002

Mathematics

JAMB

If dy/dx = 2x - 3 and y = 3 when x = 0, find y in terms of x.

A.

2x2 - 3x

B.

x2 - 3x

C.

2x2 - 3x - 3

D.

2x2 - 3x + 3

Correct Answer: 2x2 - 3x + 3

Explanation

dy/dx = 2x - 3 y = ∫2x - 3 dx => y = xx2 - 3x + c 3 = (0)2 - 3(0) + c => c = 3 Thus y = x2 - 3x + 3

dy/dx = 2x - 3 y = ∫2x - 3 dx => y = xx2 - 3x + c 3 = (0)2 - 3(0) + c => c = 3 Thus y = x2 - 3x + 3
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