2002
Mathematics
JAMB
A chord of a circle subtends an angle of 120° degrees at the centre of a circle of diameter 4√3 cm. Calculate the area of the major sector.
A.
4π cm2
B.
32 π cm2
C.
16 π cm2
D.
8 π cm2
Correct Answer: 8 π cm2
Explanation
Diameter = 4√3 cm radius = 2√3 cm Area of major sector = θ/360 × πr2 θ = 360 − 120 = 240° = 240/360 × π × 12 = 8πcm2
Diameter = 4√3 cm radius = 2√3 cm Area of major sector = θ/360 × πr2 θ = 360 − 120 = 240° = 240/360 × π × 12 = 8πcm2THIS WEEK's
Latest Articles
Top-Scorer Okoro Uchechukwu Solomon Reveals How He Scored 337 in JAMB
by samuel olalekan adeyemi
Bouncing Back: How Samuel Isaac Overcame Setbacks to Score 265 in JAMB and What He Learned
by samuel olalekan adeyemi
Managing Stress During Exams: Practical Tips for Students
by samuel olalekan adeyemi
