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Mathematics
JAMB
In how many ways can 2 students be selected from a group of 5 students in a debating competition?
A.
25 ways
B.
10 ways
C.
15 ways
D.
20 ways
Correct Answer:
10 ways
Explanation
In〖
5
〗C
2
ways =5!/((5-2)!2!) = 5!/3!2! = (5 × 4 × 3!)/(3! × 2 × 1) = 10 ways
In〖
5
〗C
2
ways =5!/((5-2)!2!) = 5!/3!2! = (5 × 4 × 3!)/(3! × 2 × 1) = 10 ways
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