2021
Mathematics
67ca00ce0c643c71d77dee1f
determine the maximum value of y=3x2 + 5x - 3
A.
6
B.
0
C.
2
D.
No correct option
Correct Answer: No correct option
Explanation
y=3x2 + 5x - 3 dy/dx = 6x + 5 as dy/dx = 0 6x + 5 = 0 x = −5/6 Maximum value: 32 (−5)/6 + 5 (−5/6) - 3 3(75/36) - 25/6 - 3 Using the L.C.M. 36 = (25 −50−36)/36 = −61/36 No correct option
y=3x2 + 5x - 3 dy/dx = 6x + 5 as dy/dx = 0 6x + 5 = 0 x = −5/6 Maximum value: 32 (−5)/6 + 5 (−5/6) - 3 3(75/36) - 25/6 - 3 Using the L.C.M. 36 = (25 −50−36)/36 = −61/36 No correct optionTHIS WEEK's
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