2022
Mathematics
67ca00ce0c643c71d77dee1f
Integrate (2x+1)3
A.
2x+13/8 + C
B.
2x+14/8 + C
C.
2x+14/4 + C
D.
2x+12/6 + C
Correct Answer: 2x+14/8 + C
Explanation
Recall chain rule: u = 2x +1; du = 2dx → dx = du/2 u3 = ∫ u3 du/2 → 1/2 ∫ u3 = 1∗u4/2∗4 = u4/8 → 2x+148 + C
Recall chain rule: u = 2x +1; du = 2dx → dx = du/2 u3 = ∫ u3 du/2 → 1/2 ∫ u3 = 1∗u4/2∗4 = u4/8 → 2x+148 + CTHIS WEEK's
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