Given that S = 3t2 + 5t - 10 is displacement of a particle in metres, calculate it initial velocity.
A.
10m/s
B.
2m/s
C.
5m/s
D.
6m/s
Correct Answer: 5m/s
Explanation
The initial velocity (v) is obtained by differentiating the displacement (S) with respect to time, which gives:
v = dS/dt= d/dt(3t2+ 5t - 10) = 6t + 5
The initial velocity is the velocity of the particle at time t = 0. Substituting t = 0 into the velocity equation:
v(0) = 6(0) + 5 = 5
Therefore, the initial velocity of the particle is 5 m/s.
The initial velocity (v) is obtained by differentiating the displacement (S) with respect to time, which gives:
v = dS/dt= d/dt(3t2+ 5t - 10) = 6t + 5
The initial velocity is the velocity of the particle at time t = 0. Substituting t = 0 into the velocity equation:
v(0) = 6(0) + 5 = 5
Therefore, the initial velocity of the particle is 5 m/s.