2022
Mathematics
67ca00ce0c643c71d77dee1f
find the limit of y = x3+6x−7/x−1 as x tends to 1
A.
9
B.
8
C.
0
D.
7
Correct Answer: 9
Explanation
x3+6x−7/(x−1): When numerator is differentiated → 3x2 + 6 When denominator is differentiated → 1 : 3x2+6/1 substitute x for 1 3∗12+6/1 = (3+6)/1 = 9/1 = 9
x3+6x−7/(x−1): When numerator is differentiated → 3x2 + 6 When denominator is differentiated → 1 : 3x2+6/1 substitute x for 1 3∗12+6/1 = (3+6)/1 = 9/1 = 9THIS WEEK's
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