2023
Mathematics
JAMB
The ages of students in a small primary school were recorded in the table below. Estimate the median.
A.
7.725
B.
6.225
C.
7.5
D.
6.5
Correct Answer: 7.725
Explanation
(N + 1)/2 = (107 + 1)/2 th = 54th value i.e the median age is in the interval "7 - 8" (29 + 25 = 54)? Median = 1m + (((∑f)/2 − fb) /fm )c lm= lower class boundary of the median age = 6.5 ∑f = 107 fb = sum of all frequencies before the median age = 29 fm = frequency of the median age = 40 c = class width = 8.5 - 6.5 = 2 Median = 6.5 + (((107/2) − 29)/40) x 2 = 6.5 + ((53.5 − 29)/40) x 2 = 6.5 + (24.5/40) x 2 = 6.5 + 1.225 ∴ median age = 7.725
(N + 1)/2 = (107 + 1)/2 th = 54th value i.e the median age is in the interval "7 - 8" (29 + 25 = 54)? Median = 1m + (((∑f)/2 − fb) /fm )c lm= lower class boundary of the median age = 6.5 ∑f = 107 fb = sum of all frequencies before the median age = 29 fm = frequency of the median age = 40 c = class width = 8.5 - 6.5 = 2 Median = 6.5 + (((107/2) − 29)/40) x 2 = 6.5 + ((53.5 − 29)/40) x 2 = 6.5 + (24.5/40) x 2 = 6.5 + 1.225 ∴ median age = 7.725THIS WEEK's
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